(2x+3)(x^2+2x-8)=0

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Solution for (2x+3)(x^2+2x-8)=0 equation: 


Simplifying
(2x + 3)(x2 + 2x + -8) = 0

Reorder the terms:
(3 + 2x)(x2 + 2x + -8) = 0

Reorder the terms:
(3 + 2x)(-8 + 2x + x2) = 0

Multiply (3 + 2x) * (-8 + 2x + x2)
(3(-8 + 2x + x2) + 2x * (-8 + 2x + x2)) = 0
((-8 * 3 + 2x * 3 + x2 * 3) + 2x * (-8 + 2x + x2)) = 0
((-24 + 6x + 3x2) + 2x * (-8 + 2x + x2)) = 0
(-24 + 6x + 3x2 + (-8 * 2x + 2x * 2x + x2 * 2x)) = 0
(-24 + 6x + 3x2 + (-16x + 4x2 + 2x3)) = 0

Reorder the terms:
(-24 + 6x + -16x + 3x2 + 4x2 + 2x3) = 0

Combine like terms: 6x + -16x = -10x
(-24 + -10x + 3x2 + 4x2 + 2x3) = 0

Combine like terms: 3x2 + 4x2 = 7x2
(-24 + -10x + 7x2 + 2x3) = 0

Solving
-24 + -10x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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